How to estimate 95 % confidence interval of population average from sample average and sample standard deviation?

If you had known average and standard deviation of sample which size is N, you could estimate the range of population average with 95 % probability. In standard normal distribution, sum of area under curve greater than 1.96 and less than – 1.96 is 0.05. There is population average between exception multiplying 1.96 by standard error from average and sum of the multiplied and average, called as 95 % confidence interval (95 % CI).

\displaystyle 95 \% C.I.= \mu \pm 1.96 SE = \mu \pm 1.96 \frac{SD}{\sqrt N}

\mu; Average, SE; standard error, SD; standard deviation