Orthogonal curvilinear coordinates. Jacobians

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The transformation equations

x = f(u_1, u_2, u_3)\ y = g(u_1, u_2, u_3)\ z = h(u_1, u_2, u_3)\cdots(17)

where we assume that f, g, h are continuous, have continuous partial derivatives and have a single-valued inverse establish a one to one correspondence between points in an xyz u_1u_2u_3 rectangular coordinate system. In vector notation the transformation (17) can be written

\bold{r} = x\bold{i} + y\bold{j} + z\bold{k} = f(u_1, u_2, u_3)\bold{i} + g(u_1, u_2, u_3)\bold{j} + h(u_1, u_2, u_3)\bold{k}\cdots (18)

A point P can be defined not only by rectangular coordinates (x, y, z) but by coordinates (u_1, u_2, u_3) as well. We call (u_1, u_2, u_3) the curvilinear coordinates of the point.

If u_2 and u_3 are constant, then as u_1 varies, \bold{r} describes a curve which we call the u_1 coordinate curve. Similarly we define the u_2 and u_3 coordinate curves through P.

From (18), we have

\displaystyle d\bold{r} = \frac{\partial\bold{r}}{\partial u_1}du_1 + \frac{\partial\bold{r}}{\partial u_2}du_2 + \frac{\partial\bold{r}}{\partial u_3}du_3 \cdots (19)

The vector \partial\bold{r}/\partial u_1 is tangent to the u_1 coordinate curve at P. If \bold{e_1} is a unit vector at P in this direction, we can write  \partial \bold{r} / \partial u_1 = h_1\bold{e_1} where h_1 = |\partial\bold{r}/\partial u_1|. Similarly we can write \partial\bold{r} / \partial u_2 = h_2\bold{e_2} and  \partial\bold{r}/\partial u_3 = h_3 \bold{e_3}, where h_2 = |\partial\bold{r}/\partial u_2| and  h_3 = |\partial\bold{r}/\partial u_3| respectively. Then (19) can be written

d\bold{r} = h_1du\bold{e_1} + h_2du\bold{e_2} + h_3du\bold{e_3}\cdots(20)

The quantities h_1, h_2, h_3 are sometimes called scale factors.

If \bold{e_1}, \bold{e_2}, \bold{e_3} are mutually perpendicular at any point P, the curvilinear coordinates are called orthogonal. In such case the element of arc length ds is given by

ds^2 = d\bold{r} \cdot d\bold{r} = h_1^2du_1^2 + h_2^2du_2^2 + h_3^2du_3^2 \cdots(21)

and corresponds to the square of the length of the diagonal in the above parallelepiped.

Also, in the case of orthogonal coordinates the volume of the parallelepiped is given by

 dV = |(h_1du_1\bold{e_1}) \cdot (h_2du_2\bold{e_2}) \times (h_3du_3\bold{e_3})| = h_1h_2h_3du_1du_2du_3 \cdots (22)

which can be written by

\displaystyle dV = \left| \frac{\partial\bold{r}}{\partial u_1} \cdot \frac{\partial\bold{r}}{\partial u_2} \times \frac{\partial\bold{r}}{\partial u_3} \right| du_1du_2du_3   = \left| \frac{\partial(x, y, z)}{\partial(u_1, u_2, u_3)} \right|du_1du_2du_3 \cdots (23)

where

\displaystyle \frac{\partial(x, y, z)}{\partial(u_1, u_2, u_3)}   = \left| \begin{array}{ccc}   \frac{\partial x}{\partial u_1} & \frac{\partial x}{\partial u_2} & \frac{\partial x}{\partial u_3} \\   \frac{\partial y}{\partial u_1} & \frac{\partial y}{\partial u_2} & \frac{\partial y}{\partial u_3} \\   \frac{\partial z}{\partial u_1} & \frac{\partial z}{\partial u_2} & \frac{\partial z}{\partial u_3} \end{array} \right|\cdots (24)

is called the Jacobian of the transformation.

It is clear that when the Jacobian is identically zero there is no parallelepiped. In such case there is a functional relationship between x, y and z, i.e. there is a function \phi such that \phi(x, y, z) = 0 identically.

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投稿者: admin

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